Q:

Bella plans to put $200 into a savings account. She can place her money into an account represented by p(x) = 3x + 200, or into another account represented by n(x) = 200(1.04)x. Which account has the highest value in 4 years? Which account has the highest in 15 years?

Accepted Solution

A:
p(x) = 3x + 200
x=4 β‡’ p(4) = 3(4)+200=12+200=212
x=15 β‡’ p(15) = 3(15)+20=45+200=245

n(x) = 200(1.04)^xx
=4 β‡’ n(4) = 200 (1.04)^4 = 233.97
x=15β‡’n(15)=200(1.04)^15 = 360.19

Then n(x) has the highest value in 4 years; n(x) has the highest value in 15 years Β